The circuit shows two capacitor $A$ and $B$ of capacitances $C$ and $2 C$ respectively.
When they are fully charged, the cell is removed and the capacitors are connected with their plates of opposite polarities touching each other. Then
(i) Charge on $A$ is $\frac{4 C E}{9}$
(ii) Charge on $B$ is zero
(iii) Loss of energy in this process is $\left(C E^2 / 3\right)$
The correct statement/s is/are

A uniform conducting wire $A B$ of length 5 m and resistance $5 \Omega$ is connected as shown in the circuit. If the balancing point is obtained at 3 m from $A$, then the value of $E$ is

In the given circuit, the equivalent resistance between $A$ and $B$ is

A square loop of side $a$ and carrying a current $I$ is suspended from an insulating hanger of a spring balance as shown in figure. The transverse magnetic field $B$ directed into the paper occurs only at the bottom side of the loop. When direction of current in the loop is reversed, the change in the reading of spring balance is

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