1
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The graph given in the figure shows the variation of photo current $(I)$ and the applied voltage ( $V$ ) for two different materials and for two different intensities of the incident radiations. Then the curves which represent the same material are

TS EAMCET 2023 (Online) 14th May Evening Shift Physics - Dual Nature of Radiation Question 21 English

A

1 and 3

B

1 and 4

C

2 and 3

D

3 and 4

2
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Half-life of a radioactive substance $A$ is two times the half-life of another radioactive substance $B$. Initially the number of nuclei of $A$ and $B$ are $N_A$ and $N_B$ respectively. After three half-lives of $A$, the number of nuclei of both are equal. Then $N_A / N_B$ is

A

$1 / 3$

B

$1 / 4$

C

$1 / 6$

D

$\frac{1}{8}$

3
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When an $n$-type semiconductor is heated

A

number of electrons increases while that of electrons decreases

B

number of holes increases while that of electrons decreases

C

number of holes and electrons do not change

D

number of holes and electrons increases equally

4
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

5 logic gates are connected as shown in the figure. If $A$ and $B$ are the inputs, $Y$ is the output then the truth table of the circuit is

TS EAMCET 2023 (Online) 14th May Evening Shift Physics - Semiconductor Devices and Logic Gates Question 24 English

A

$$ \begin{array}{|l|l|l|} \hline \text { A } & \text { B } & \text { Y } \\ \hline 0 & 0 & 0 \\ \hline 1 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 1 & 0 \\ \hline \end{array} $$

B

$$ \begin{array}{|l|l|l|} \hline \text { A } & \text { B } & \text { Y } \\ \hline 0 & 0 & 1 \\ \hline 1 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

C

$$ \begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ \hline 1 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

D

$$ \begin{array}{|l|l|l|} \hline \mathbf{A} & \mathbf{B} & \mathbf{Y} \\ \hline 0 & 0 & 1 \\ \hline 1 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 1 & 1 \\ \hline \end{array} $$

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