A bar magnet of magnetic moment $2 \mathrm{~A}-\mathrm{m}^2$ lies aligned with the direction of a uniform magnetic field of 0.3 T . The amount of work required by an external torque to turn the magnet so as to align its magnetic moment normal to the field direction is
A conducting rod is moving towards right with a velocity $v$ in a uniform magnetic field $B$. If the direction of induced current $i$ is as shown in the figure, then the direction of $B$ is

A coil has a resistance of $30 \Omega$ and an inductive reactance of $20 \Omega$ at 50 Hz frequency. If an AC source of $200 \mathrm{~V}, 100 \mathrm{~Hz}$ is connected across the coil, the current in the coil is
A current $i$ is flowing through a wire of length ' $L$ '. If it is made into a circular loop of one turn, then its magnetic moment is
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