1
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Assertion (A) In $\triangle A B C$, if $r=6, r_2=36, R=15$, then $c^2+a^2=b^2$.

Reason (R) In $\triangle A B C$, if $r: R: r_2=1: 2.5: 6$, then $B=90^{\circ}$. The correct option among the following is

A

Both (A) and (R) are true, (R) is a correct explanation of (A)

B

Both $(A)$ and $(R)$ are true, but $(R)$ is not a correct explanation of (A)

C

(A) is true and (R) is false

D

(A) is false and (R) is true

2
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\mathbf{a}, \mathbf{b}, \mathbf{c}$ are unit vectors such that $\mathbf{a}$ is perpendicular to both $\mathbf{b}, \mathbf{c}$ and angle between $\mathbf{b}, \mathbf{c}$ is $2 \pi / 3$, then $|a+3 b-4 c|^2=$

A

6

B

14

C

38

D

26

3
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $\mathbf{a}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}$ be the position vector of a point $A$. Let $\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}$ and $\mathbf{c}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}$ be two vectors and $\mathbf{r}$ be a vector passing through the point $A(\mathbf{a})$ and parallel to the vector $\mathbf{b}$. If the projection of $\mathbf{r}$ on $\mathbf{c}$ is $\frac{9}{\sqrt{6}}$, then $|\mathbf{r}|=$

A

$\sqrt{26}$

B

5

C

$\sqrt{5}$

D

$\sqrt{34}$

4
TS EAMCET 2023 (Online) 14th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $S$ is the circumcentre, $O$ is the orthocentre and $G$ is the centroid of a $\triangle A B C$, then match the items of the List-I with those of the items of List-II given below.

List-I List-II
(i)
<mi data-mjx-auto-op="false">SA</mi>
+
<mi data-mjx-auto-op="false">SB</mi>
+
<mi data-mjx-auto-op="false">SC</mi>
<mi data-mjx-auto-op="false">SA</mi>
+
<mi data-mjx-auto-op="false">SB</mi>
+
<mi data-mjx-auto-op="false">SC</mi>
SA+SB+SC
(a) 2 OS
(ii)
<mi data-mjx-auto-op="false">GA</mi>
+
<mi data-mjx-auto-op="false">GB</mi>
+
<mi data-mjx-auto-op="false">GC</mi>
<mi data-mjx-auto-op="false">GA</mi>
+
<mi data-mjx-auto-op="false">GB</mi>
+
<mi data-mjx-auto-op="false">GC</mi>
GA+GB+GC
(b) 2
<mo>/</mo>
3
<mi data-mjx-auto-op="false">OS</mi>
2
<mo>/</mo>
3
<mi data-mjx-auto-op="false">OS</mi>
2//3OS
(iii)
<mi data-mjx-auto-op="false">OA</mi>
+
<mi data-mjx-auto-op="false">OB</mi>
+
<mi data-mjx-auto-op="false">OC</mi>
<mi data-mjx-auto-op="false">OA</mi>
+
<mi data-mjx-auto-op="false">OB</mi>
+
<mi data-mjx-auto-op="false">OC</mi>
OA+OB+OC
(c) O
(iv) OG (d) SO
(e) OS

Then, the correct match is

A

i $\rightarrow$ c, ii $\rightarrow$ b, iii $\rightarrow$ e, iv $\rightarrow$ a

B

i $\rightarrow$ b, ii $\rightarrow$ c, iii $\rightarrow$ a, iv $\rightarrow$ d

C

i $\rightarrow$ d, ii $\rightarrow$ a, iii $\rightarrow$ c, iv $\rightarrow$ e

D

i → d, ii → c, iii → a, iv → b

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