On treating $\mathrm{SO}_2$ with aqueous solution of $\mathrm{KMnO}_4$, the manganese ion reduces to

$$ \text { Match the following. } $$

$$ \begin{array}{lcll} \hline & \text { Column-I (Molecule) } & & \text { Column-II (Colour) } \\ \hline \text { (A) } & \mathrm{F}_2 & \text { (I) } & \text { Red } \\ \hline \text { (B) } & \mathrm{Cl}_2 & \text { (II) } & \text { Violet } \\ \hline \text { (C) } & \mathrm{Br}_2 & \text { (III) } & \text { Yellow } \\ \hline \text { (D) } & \mathrm{I}_2 & \text { (IV) } & \text { Greenish yellow } \\ \hline \end{array} $$

$$ \text { The correct match is } $$

The correct decreasing order of the following ' Xe ' compounds to act as both fluorinating and oxidising agent is

(i) $\mathrm{XeF}_6$

(ii) $\mathrm{XeF}_4$

(iii) $\mathrm{XeF}_2$

The correct order of ionic radii of trivalent ions $\mathrm{Y}^{3+}, \mathrm{La}^{3+}, \mathrm{Eu}^{3+}$ and $\mathrm{Lu}^{3+}$ is $(\mathrm{Y}=39, \mathrm{La}=57, \mathrm{Eu}=63, \mathrm{Lu}=71)$