1
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Assertion (A) The image of $\frac{x^2}{25}+\frac{y^2}{16}=1$ in the line $x+y=10$ is $\frac{(x-10)^2}{16}+\frac{(y-10)^2}{25}=1$

Reason ( $\mathbf{R}$ ) The image of a curve ' $C$ ' in a line $L$ is the locus of the image of every point of $C$ with respect to the line $L$. The correct option among the following is :

A

(A) is true, (R) is true and (R) is the correct explanation for (A)

B

(A) is true, (R) is true but (R) is not the correct explanation for (A)

C

(A) is true but (R) is false

D

(A) is false but (R) is true

2
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the latusrectum of a hyperbola subtends an angle of $120^{\circ}$ at its centre, then its eccentricity is

A

$\frac{\sqrt{3}+2}{\sqrt{2}}$

B

$\frac{\sqrt{3}+\sqrt{5}}{2}$

C

$\frac{\sqrt{3}-\sqrt{2}}{3}$

D

$\frac{\sqrt{3}+\sqrt{7}}{2}$

3
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $P\left(\frac{\pi}{4}\right), Q\left(\frac{5 \pi}{4}\right), R\left(\frac{3 \pi}{4}\right), T\left(\frac{7 \pi}{4}\right)$ be the points on the hyperbola $x^2-4 y^2-4=0$ in the parametric form. Then the area of the quadrilateral $P Q R T$ is (in square units)

A

$4 \sqrt{2}$

B

$16 \sqrt{2}$

C

$32 \sqrt{2}$

D

$8 \sqrt{2}$

4
TS EAMCET 2022 (Online) 19th July Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $A(1,2,3), B(2,-3,1), C(3,2,-1)$ are three vertices of a tetrahedron $A B C D$ and $G\left(\frac{5}{2}, \frac{3}{2}, \frac{9}{4}\right)$ is its centroid, then the point which divides $G D$ in the ratio $1: 2$ is

A

$(6,1,3)$

B

$\left(3, \frac{8}{3}, 3\right)$

C

$\left(\frac{1}{3}, \frac{2}{3}, 1\right)$

D

$\left(3, \frac{8}{3}, \frac{7}{2}\right)$

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