A metal has $9 \times 10^{28}$ conduction electrons per $m^3$ and its resistivity is $1 \times 10^{-8} \Omega \mathrm{~m}$. If the drift speed of an electron in the metal is $1.6 \times 10^6 \mathrm{~m} / \mathrm{s}$, then its mean free path is (mass of electron $=9 \times 10^{-31} \mathrm{~kg}$ and charge of electron $=1.6 \times 10^{-19} \mathrm{C}$ )
The resistivity of a metal is $1 \times 10^{-8} \Omega-\mathrm{m}$. If it contains $9 \times 10^{28}$ electrons per $\mathrm{m}^3$, then the relaxation time of electrons inside the metal is nearly
(electron mass $=9 \times 10^{-31} \mathrm{~kg}$ )
A particle of mass $m$ and charge $q$ travelling with a velocity $v$ along the $X$-axis enters a uniform electric field $\mathbf{E}$ directed along the $Y$-axis. What will be the trajectory of the particle?
A long solenoid with 10.0 turn $/ \mathrm{cm}$ and a radius of 8 cm carries a current of 7 mA . A current carrying straight conductor is located along the central axis of the solenoid. If the direction of resulting magnetic field is $60^{\circ}$ to axial direction at a point 5 cm from the axis of the solenoid along the radial direction, then the current in the conductor is [take, $\sqrt{2}=1.4, \sqrt{3}=1.7$ ]
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