1
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The roots of the equation $x^{3}-3 x^{2}+3 x+7=0$ are $\alpha, \beta, \lambda$ and $\omega, \omega^{2}$ are complex cube roots of unity, If the terms containing $x^{2}$ and $x$ are missing in the transformed equation when each one of these roots is decreased by $h$, then $\frac{\alpha-h}{\beta-h}+\frac{\beta-h}{\gamma-h}+\frac{\gamma-h}{\alpha-h}=$
A
$\frac{3}{\omega^{2}}$
B
$3 \omega$
C
0
D
$3 \omega^{2}$
2
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

With respect to the roots of the equation $3 x^{3}+b x^{2}+b x+3=0$, match the items of List I with those fo List II

List I List II
A All the roots are negative. I. $(b-3)^2=36+P^2$ for $P \in R$
B Two roots are complex. II. $-3<b<9$
C Two roots are positive. III. $b \in(-\infty,-3) \cup(9, \infty)$
D All roots are real and IV. $b=9$
V. $b=-3$
A
A - V, B - III, C - I, D- II
B
A - IV, B - I, C - II, D- III
C
A - V, B - II, C - III, D-I
D
A - IV, B - II, C - V, D- III
3
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The number of ways of arranging all the letters of the word 'COMBINATIONS' around a circle so that no two vowels together is
A
$\frac{7!6!}{(2!)^{4}}$
B
$\frac{7!6!}{(2!)^{3}}$
C
$\frac{{ }^{8} P_{5} \times 6!}{(2!)^{3}}$
D
$\frac{7!x^{8} P_{5}}{(2!)^{3}}$
4
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If all the numbers which are greater than 6000 and less than 10000 are formed with the digits, $3,5,6,7,8$ without repetition of the digits, then the difference between the number of odd numbers and the number of even number among them is
A
${ }^{4} P_{3}$
B
$3\left({ }^{4} P_{2}\right)$
C
${ }^{5} P_{3}$
D
$2\left({ }^{4} P_{3}\right)$
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