1
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The number of ways of arranging all the letters of the word 'COMBINATIONS' around a circle so that no two vowels together is
A
$\frac{7!6!}{(2!)^{4}}$
B
$\frac{7!6!}{(2!)^{3}}$
C
$\frac{{ }^{8} P_{5} \times 6!}{(2!)^{3}}$
D
$\frac{7!x^{8} P_{5}}{(2!)^{3}}$
2
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If all the numbers which are greater than 6000 and less than 10000 are formed with the digits, $3,5,6,7,8$ without repetition of the digits, then the difference between the number of odd numbers and the number of even number among them is
A
${ }^{4} P_{3}$
B
$3\left({ }^{4} P_{2}\right)$
C
${ }^{5} P_{3}$
D
$2\left({ }^{4} P_{3}\right)$
3
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
A man has 7 relatives, 4 of them are ladies and 3 gents; his wife has 7 other relatives, 3 of them are ladies and 4 gents. The number of ways they can invite them to a party of 3 ladies and 3 gents so that the there are 3 of man's relatives and 3 of wife's relatives, is
A
$341^{\circ}$
B
161
C
485
D
435
4
TG EAPCET 2024 (Online) 10th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the coefficient fo $x^{r}$ in the expansion of $\left(1+x+x^{2}+x^{3}\right)^{100}$ is $a_{r}$ and $S=\sum_{r=0}^{300} a_{r}$ then $\sum_{r=0}^{300} r \cdot a_{r}=$
A
(50) S
B
$(25) \mathrm{S}$
C
$(150) \mathrm{S}$
D
$(100) \mathrm{S}$
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