MHT CET 2026 18th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 18th April Evening Shift

MCQ (Single Correct Answer)

-0

The rate of disintegration of a radioactive element at any time is proportional to its mass at that time, where $k$ $(k>0)$ is the constant of proportionality. The time during which an original mass of 1.5 gm will disintegrate to a mass of 0.5 gm is $\ldots$

$k\log 3$

$\dfrac{1}{k}\log 3$

$k\log 5$

$\dfrac{1}{k}\log 5$

MHT CET 2026 18th April Evening Shift

MCQ (Single Correct Answer)

-0

The differential equation of the family of all parabolas whose axis is the $y$-axis is $\ldots$

$\dfrac{d^2y}{dx^2} + x\dfrac{dy}{dx} = 0$

$x\dfrac{d^2y}{dx^2} - \dfrac{dy}{dx} = 0$

$\dfrac{d^2y}{dx^2} - x\dfrac{dy}{dx} = 0$

$x\dfrac{d^2y}{dx^2} + \dfrac{dy}{dx} = 0$

MHT CET 2026 18th April Evening Shift

MCQ (Single Correct Answer)

-0

The integrating factor of the differential equation $x\dfrac{dy}{dx} + 2y = x^2 \log x$ is

$x^3$

$x^2$

$\log 2x$

$\log x^2$

MHT CET 2026 18th April Evening Shift

MCQ (Single Correct Answer)

-0

A spherical raindrop evaporates at a rate proportional to its surface area. The differential equation involving the rate of change of its radius $r$ with time '$t$' is $\ldots$ (where $k$ is a positive constant)

$\dfrac{dr}{dt} + k = 0$

$\dfrac{dr}{dt} - k = 0$

$\dfrac{dr}{dt} + kr = 0$

$\dfrac{dr}{dt} - kr = 0$

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