1
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
When cell of E.M.F. '$E_1$' is connected to potentiometer wire the balancing length is '$l_1$'. Another cell of E.M.F. '$E_2$' ($E_1 > E_2$) is connected along with $E_1$ so as two cells oppose each other, the balancing length is '$l_2$'. The ratio $E_1 : E_2$ is
A
$(l_1) : (l_1 + l_2)$
B
$(l_1) : (l_1 - l_2)$
C
$(l_1 + l_2) : (l_1)$
D
$(l_1 + l_2) : (l_1 - l_2)$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In the following network,
$I_1 = -0.4\,\text{A}$ , $I_4 = 1\,\text{A}$ , $I_5 = 0.4\,\text{A}$
The values of $I_2$, $I_3$ and $I_6$ are respectively
MHT CET 2026 18th April Evening Shift Physics - Current Electricity Question 3 English
A
$1.4\,\text{A}$ , $0.4\,\text{A}$ , $-0.6\,\text{A}$
B
$0.4\,\text{A}$ , $-0.6\,\text{A}$ , $1.4\,\text{A}$
C
$1.4\,\text{A}$ , $-0.6\,\text{A}$ , $0.4\,\text{A}$
D
$-0.6\,\text{A}$ , $1.4\,\text{A}$ , $0.4\,\text{A}$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon
A
q and m
B
$\omega$ and m
C
$\omega$ and q
D
$\omega$ , q and m
4
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A straight long wire is carrying current I. The ratio of magnetic field due to this wire at perpendicular distance 2 cm and 5 cm respectively from the wire is
A
$2:5$
B
$3:5$
C
$7:3$
D
$5:2$

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