1
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A kathak dancer is standing on horizontal surface with folded hands. In the begining dancer is rotating about his central axis and his kinetic energy is 'K' at that time. The kathak dancer now stretches his arms so that the moment of inertia of the dancer becomes three times and the angular velocity becomes one-third. The kinetic energy of the dancer now is
A
$\dfrac{K}{6}$
B
$\dfrac{K}{3}$
C
$3K$
D
$6K$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A solid sphere rolls without slipping on an inclied plane at an angle $\theta$. The ratio of total kinetic energy to its rotational kinetic energy is
A
$\dfrac{5}{2}$
B
$\dfrac{7}{2}$
C
$\dfrac{5}{4}$
D
$\dfrac{5}{7}$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The acceleration due to gravity at a height 'h' above the surface of earth is '$g_h$'. At the depth 90 km below the earth's surface the acceleration due to gravity is also '$g_h$'. The value of 'h' is
A
$180$ km
B
$120$ km
C
$90$ km
D
$45$ km
4
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
An incompressible fluid (ideal fluid) is flowing through non uniform cross-sectional tube PQ as shown in the figure from end P to end Q. If $K_P$ and $K_Q$ are the kinetic energy per unit volume of the fluid at end P and end Q respectively, then
MHT CET 2026 18th April Evening Shift Physics - Fluid Mechanics Question 6 English
A
$K_P = \dfrac{1}{2}K_Q$
B
$K_P = K_Q$
C
$K_P < K_Q$
D
$K_P > K_Q$

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