1
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
For $x > 0$ and $(x \log x) < 1$, if $y = \cot^{-1}\left(\dfrac{x - \log x^{x^2}}{\log e^{x^2} + \log x^x}\right)$, then $\dfrac{dy}{dx} = \ldots$
A
$\dfrac{1}{1+x^2} + \dfrac{2}{x[1+(\log x)^2]}$
B
$\dfrac{1}{1+x^2} + \dfrac{1}{x[1+(\log x)^2]}$
C
$\dfrac{-1}{1+x^2} + \dfrac{1}{x[1+(\log x)^2]}$
D
$\dfrac{1}{1+x^2} + \dfrac{1}{[1+(\log x)^2]}$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
For $x > 0$, if $\sin(\cos^{-1}x + \tan^{-1}x) - \cos(\sin^{-1}x + \tan^{-1}x) = \sin(\cot^{-1}2)$ then $x = $
A
$\dfrac{1}{\sqrt{2}}$
B
$\dfrac{1}{2}$
C
$\dfrac{\sqrt{3}}{2}$
D
$1$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\tan^{-1}ax + \tan^{-1}3x = \dfrac{\pi}{4}$, where $3ax^2 < 1$, then value of $a$ for $x = \dfrac{1}{6}$ is $\ldots$
A
$2$
B
$3$
C
$4$
D
$9$
4
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\sec^2(\tan^{-1}3) - \tan^2(\sec^{-1}3) = $
A
$0$
B
$1$
C
$2$
D
$3$

MHT CET Papers

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