1
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The plane $\dfrac{x}{2} + \dfrac{y}{3} + \dfrac{z}{4} = 1$ cuts the co-ordinate axes at the points A, B, C respectively. Then the area of triangle ABC is
A
$\sqrt{61}$ sq. units
B
$\dfrac{\sqrt{61}}{2}$ sq. units
C
$\dfrac{\sqrt{61}}{4}$ sq. units
D
$\dfrac{\sqrt{71}}{2}$ sq. units
2
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In L.P.P., the corner points of the feasible region for the constraints $3x - y \geq 6, x \leq 3, y \leq 2, y \geq 0, x \geq 0$ are .....
A
$(3, 2), (3, 0), (2, 0)$
B
$\left(\dfrac{8}{3}, 2\right), (3, 2), (3, 0), (2, 0)$
C
$(0, 0), (2, 0), \left(\dfrac{8}{3}, 2\right), (0, 2)$
D
$(3, 2), (0, 3), (0, 2)$
3
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The odds in favour of A winning a game of table tennis against B are 1:2. If 3 games are to be played, then the probability of A winning at least two games out of the three is.....
A
$\dfrac{1}{27}$
B
$\dfrac{2}{27}$
C
$\dfrac{5}{27}$
D
$\dfrac{7}{27}$
4
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
A random variable X has the following probability distribution
$X = x$$1$$2$$3$$4$$5$$6$$7$$8$
$P(X=x)$$0.15$$0.23$$0.10$$0.12$$0.20$$0.08$$0.07$$0.05$

For the events $E = \{X \text{ is a prime number}\}$, $F = \{X < 4\}$, $P(E \cup F)$ is
A
$0.5$
B
$0.77$
C
$0.35$
D
$0.75$

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