MHT CET 2026 13th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

A body is projected vertically from earth's surface of radius R with velocity equal to half the escape velocity. The maximum height reached by the body is

$\dfrac{R}{3}$

$R$

$\dfrac{R}{2}$

$\dfrac{R}{4}$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

Two small drops of liquid of same radius coalesce to form a big drop. The ratio of the total surface energies after and before the change is

$2 : 1$

$\sqrt{2} : 1$

$2^{-1/3} : 1$

$1 : 2$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

Three liquids have same surface tension and have densities $\rho_1, \rho_2$ and $\rho_3$ $(\rho_1 > \rho_2 > \rho_3)$. In three identical capillaries rise of liquid is same. The corresponding angles of contact $\theta_1, \theta_2$ and $\theta_3$ are related as

$\theta_1 > \theta_2 > \theta_3$

$\theta_1 < \theta_2 < \theta_3$

$\theta_1 = \theta_2 = \theta_3$

$\theta_1 > \theta_2 < \theta_3$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The work done in splitting a water drop of radius 'R' into 64 droplets is (T is the surface tension of water)

$8\pi R^2 T$

$12\pi R^2 T$

$4\pi R^2 T$

$16\pi R^2 T$