1
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\displaystyle\int \dfrac{\sin 2x}{\sin^4 x + \cos^4 x} \, dx = f(x) + c$ where c is constant of integration, then the value of $\tan(f(x))$ is
A
$\tan x$
B
$\tan^2 x$
C
$\tan^4 x$
D
$\cot^4 x$
2
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
$\displaystyle\int e^{2x} \dfrac{2(\sin 2x \cos 2x - 1)}{2 \sin^2 2x} \, dx = A \, e^{2x} \cot 2x + c$
(Where c is the constant of integration.), then $A^3 =$
A
$\dfrac{1}{8}$
B
$64$
C
$8$
D
$\dfrac{1}{64}$
3
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\displaystyle\int_0^a \dfrac{dx}{1 + 4x^2} = \dfrac{\pi}{8}$, then $a =$
A
$\dfrac{1}{3}$
B
$\dfrac{1}{2}$
C
$\dfrac{1}{4}$
D
$1$
4
MHT CET 2026 13th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of the integral $\displaystyle\int_{-\sqrt{3}}^{\sqrt{3}} \dfrac{(2x^9 + 3x^8 - 5x^7 + 9x^6 + 4x^3 - x + 3)}{x^2 + 3} \, dx$ is
A
$\dfrac{162}{7} + \sqrt{3} \dfrac{\pi}{4}$
B
$\dfrac{162\sqrt{3}}{7} + \sqrt{3} \dfrac{\pi}{2}$
C
$\dfrac{162\sqrt{3}}{7} + \dfrac{\pi}{2}$
D
$\dfrac{162\sqrt{3}}{7} - \dfrac{\pi}{2}$

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