MHT CET 2026 13th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The point having position vector $4\hat{i} - 11\hat{j} + 2\hat{k}$ lies on the line

$\bar{r} = (6\hat{i} - 4\hat{j} + 5\hat{k}) + \lambda(\hat{i} + 7\hat{j} + 3\hat{k})$

$\bar{r} = (6\hat{i} - 4\hat{j} + 5\hat{k}) + \lambda(2\hat{i} + \hat{j} + 3\hat{k})$

$\bar{r} = (6\hat{i} - 4\hat{j} + 5\hat{k}) + \lambda(2\hat{i} + 3\hat{j} + \hat{k})$

$\bar{r} = (6\hat{i} - 4\hat{j} + 5\hat{k}) + \lambda(2\hat{i} + 7\hat{j} + 3\hat{k})$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The shortest distance between the lines, where the first line passes through $(0,0,0)$ and $(2,0,3)$ and the second line passes through $(2,5,0)$ and $(0,4,0)$ is

$\dfrac{24}{7}$ units

$\dfrac{9}{7}$ units

$\dfrac{1}{7}$ units

$\dfrac{36}{7}$ units

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The co-ordinates of the foot of the perpendicular from the origin to the plane $2x - 3y - 6z = 49$ are...

$(2, -3, -6)$

$\left(\dfrac{2}{7}, \dfrac{-3}{7}, \dfrac{-6}{7}\right)$

$(-2, 3, 6)$

$\left(\dfrac{-2}{7}, \dfrac{3}{7}, \dfrac{6}{7}\right)$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

Let a plane P pass through the point $(3, 7, -7)$ and contain the line $\dfrac{x - 2}{-3} = \dfrac{y - 3}{2} = \dfrac{z + 2}{1}$. If the distance of the plane P from the origin is d, then $d^2$ is

$2$

$3$

$4$

$6$

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