MHT CET 2026 13th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

If $\dfrac{dy}{dx} = y + 5$ and $y(0) = 4$ then $y(\log 2)$ is equal to

$2$

$5$

$7$

$13$

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

The solution of the differential equation $\dfrac{dy}{dx} = \dfrac{x+y}{x-y}$ is

$c(x^2 + y^2)^{\frac{1}{2}} + e^{\tan^{-1}\left(\frac{y^2}{x}\right)} = 0$, where c is an arbitrary constant

$c(x^2 + y^2)^{\frac{1}{2}} = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constant

$c(x^2 - y^2) = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constant

$c(x^2 + y^2) = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constant

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

A spherical balloon expands at a rate proportional to its surface area. Initially its radius is 2 cm and 5 minutes later it increases upto 7 cm, then surface area of spherical balloon after 12 minutes will be

$2480$ sq.cm.

$2460$ sq.cm.

$2464$ sq.cm.

$2400$ sq.cm.

MHT CET 2026 13th April Morning Shift

MCQ (Single Correct Answer)

-0

Let $\bar{a}, \bar{b}, \bar{c}$ be three vectors having magnitudes 1, 1 and 2 respectively. If $\bar{a} \times (\bar{a} \times \bar{c}) + \bar{b} = \bar{0}$, then the acute angle between $\bar{a}$ and $\bar{c}$ is

$\dfrac{\pi}{4}$

$\dfrac{\pi}{6}$

$\dfrac{\pi}{3}$

$\dfrac{\pi}{8}$

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