1
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Identify the product formed in the following reaction,

$$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CHO} \mathrm{\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{(ii)\,{H_2}{O^ + }}^{(i)\,LiAl{H_4}}}} \text {Products }$$

A
$$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{OH}$$
B
$$\mathrm{CH}_3-\left(\mathrm{CH}_2\right)_3-\mathrm{CH}_2-\mathrm{OH}$$
C
$$\mathrm{CH}_3-\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{OH}$$
D
$$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}$$
2
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\sin ^{-1}\left[\sin \left(-600^{\circ}\right)\right]+\cot ^{-1}(-\sqrt{3})=$$

A
$$\frac{\pi}{6}$$
B
$$\frac{\pi}{4}$$
C
$$\frac{\pi}{3}$$
D
$$\frac{7 \pi}{6}$$
3
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{m}$$ is order and $$\mathrm{n}$$ is degree of the differential equation $$y=\frac{d p}{d x}+\sqrt{a^2 p^2-b^2}$$, where $$p=\frac{d y}{d x}$$, then the value of $$m+n$$ is

A
2
B
3
C
4
D
5
4
MHT CET 2021 20th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

The surface area of a spherical balloon is increasing at the rate $$2 \mathrm{~cm}^2 / \mathrm{sec}$$. Then rate of increase in the volume of the balloon is , when the radius of the balloon is $$6 \mathrm{~cm}$$.

A
$$4 \mathrm{~cm}^3 / \mathrm{sec}$$.
B
$$16 \mathrm{~cm}^3 / \mathrm{sec}$$.
C
$$36 \mathrm{~cm}^3 / \mathrm{sec}$$.
D
$$6 \mathrm{~cm}^3 / \mathrm{sec}$$.
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