MHT CET 2020 19th October Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

Using Bohr's model, the orbital period of electron in hydrogen atom in $n$th orbit is ( $\varepsilon_0=$ permittivity of free space, $h=$ Planck's constant, $m=$ mass of electron and $\theta=$ electronic charge)

$\frac{2 \varepsilon_0^2 n^3 h^3}{m e^4}$

$\frac{8 \varepsilon_0^2 n^3 h^3}{m e^4}$

$\frac{2 \varepsilon_0 n^2 h^2}{m e^4}$

$\frac{4 \varepsilon_0^2 n^3 h^3}{m e^4}$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

Let $\sigma$ and $b$ be Stefan's constant and Wien's constant respectively, then dimensions of $\sigma b$ are

$\left[L^1 M^{-1} T^{-3} K^{-3}\right]$

$\left[L^1 M^1 T^3 K^{-3}\right]$

$\left[L^{-1} M^1 \mathrm{~T}^{-3} \mathrm{~K}^{-3}\right]$

$\left[L^1 M^1 T^{-3} K^{-3}\right]$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

At the poles, a stretched wire of a given length vibrates in unison with a tuning fork. At the equator, for same setting to produce resonance with same fork, the vibrating length of wire

should be same

should be increased

should be decreased

should be 3 times the original length

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

A steel wire of length / has a magnetic moment $M$. It is then bent into a semicircular arc. The new magnetic moment is

$M \times \ell$

$\frac{M}{\ell}$

$\frac{2 M}{\pi}$

$M$