1
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $x^2 y^2=\sin ^{-1} \sqrt{x^2+y^2}+\cos ^{-1} \sqrt{x^2+y^2}$ then $\frac{d y}{d x}=$

A
$\frac{-x}{y}$
B
$\frac{x}{y}$
C
$\frac{-y}{x}$
D
$\frac{y}{x}$
2
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\int_\limits0^{\frac{\pi}{2}} \frac{\sqrt[7]{\sin x}}{\sqrt[7]{\sin x}+\sqrt[7]{\cos x}} d x=$$

A
$\frac{\pi}{8}$
B
$\frac{\pi}{3}$
C
$\frac{\pi}{4}$
D
$\frac{\pi}{2}$
3
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

$\int_\limits0^1\left(1-\frac{x}{1!}+\frac{x^2}{2!}-\frac{x^3}{3!}+\ldots\right.$ upto $\left.\infty\right) e^{2 x} d x=$

A
$e^2$
B
$e+1$
C
$e$
D
$e-1$
4
MHT CET 2020 19th October Evening Shift
MCQ (Single Correct Answer)
+2
-0

The principal solutions of $\cot x=\sqrt{3}$ are

A
$\frac{\pi}{6}, \frac{7 \pi}{6}$
B
$\frac{\pi}{3}, \frac{7 \pi}{3}$
C
$\frac{\pi}{4}, \frac{5 \pi}{4}$
D
$\frac{\pi}{6}, \frac{5 \pi}{6}$
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