The given equation is:

$$ \frac{{\log \,P}}{{y - z}} = \frac{{\log \,Q}}{{z - x}} = \frac{{\log \,R}}{{x - y}} = 10 $$

Let's denote this common value by $$k = 10$$. Therefore, we can write:

$$ \frac{{\log \,P}}{{y - z}} = k \implies \log \,P = k(y - z) $$

$$ \frac{{\log \,Q}}{{z - x}} = k \implies \log \,Q = k(z - x) $$

$$ \frac{{\log \,R}}{{x - y}} = k \implies \log \,R = k(x - y) $$

Now, let's sum these three equations:

$$ \log \,P + \log \,Q + \log \,R = k(y - z) + k(z - x) + k(x - y) $$

The right-hand side simplifies as follows:

$$ k(y - z + z - x + x - y) = k \cdot 0 = 0 $$

Thus, we have:

$$ \log \,P + \log \,Q + \log \,R = 0 $$

Using properties of logarithms, this can be rewritten as:

$$ \log (PQR) = 0 $$

Exponentiating both sides of the equation (with base 10), we get:

$$ 10^{\log (PQR)} = 10^0 $$

Therefore:

$$ PQR = 1 $$

Thus, the value of the product $$PQR$$ is $$1$$. The correct option is:

Option B: 1