KCET 2023 | Thermodynamics Question 2 | Chemistry

Lattice enthalpy for $$\mathrm{NaCl}$$ is $$+788 \mathrm{~kJ} \mathrm{~mol}^{-1}$$ and $$\Delta H_{\text {hyd }}^{\circ}=-784 \mathrm{~kJ} \mathrm{~mol}^{-1}$$. Enthalpy of solution of $$\mathrm{NaCl}$$ is

$$+572 \mathrm{~kJ} \mathrm{~mol}^{-1}$$

$$+4 \mathrm{~kJ} \mathrm{~mol}^{-1}$$

$$-572 \mathrm{~kJ} \mathrm{~mol}^{-1}$$

$$-4 \mathrm{~kJ} \mathrm{~mol}^{-1}$$

KCET 2023

MCQ (Single Correct Answer)

-0

Temperature of $$25^{\circ} \mathrm{C}$$ in Fahrenheit and Kelvin scale respectively are

$$77^{\circ} \mathrm{F}$$ and $$298.15 \mathrm{~K}$$

$$17^{\circ} \mathrm{F}$$ and $$298.15 \mathrm{~K}$$

$$45^{\circ} \mathrm{F}$$ and $$260.15 \mathrm{~K}$$

$$47^{\circ} \mathrm{F}$$ and $$312.15 \mathrm{~K}$$

KCET 2022

MCQ (Single Correct Answer)

-0

The work done when 2 moles of an ideal gas expands rèversibly and isothermally from a volume of $$1 \mathrm{~L}$$ to $$10 \mathrm{~L}$$ at $$300 \mathrm{~K}$$ is ($$R=0.0083 \mathrm{~kJ} \mathrm{~K} \mathrm{~mol}^{-1}$$)

5.8 kJ

0.115 kJ

58.5 kJ

11.5 kJ

KCET 2020

MCQ (Single Correct Answer)

-0

When the same quantity of heat is absorbed by a system at two different temperatures $$T_1$$ and $$T_2$$, such that $$T_1>T_2$$, change in entropies are $$\Delta S_1$$ and $$\Delta S_2$$ respectively. Then

$$\Delta S_1<\Delta S_2$$

$$\Delta S_1=\Delta S_2$$

$$S_1>S_2$$

$$\Delta S_2<\Delta S_1$$

PREVIOUS NEXT

KCET Subjects