1
KCET 2022
MCQ (Single Correct Answer)
+1
-0

Crystal field splitting energy (CFSE) for $$\left[\mathrm{CoCl}_6\right]^{4-}$$ is $$18000 \mathrm{~cm}^{-1}$$. The crystal field splitting energy (CFSE) for $$\left[\mathrm{CoCl}_4\right]^{2-}$$ will be

A
$$16000 \mathrm{~cm}^{-1}$$
B
$$8000 \mathrm{~cm}^{-1}$$
C
$$10000 \mathrm{~cm}^{-1}$$
D
$$18000 \mathrm{~cm}^{-1}$$
2
KCET 2022
MCQ (Single Correct Answer)
+1
-0

The complex hexamineplatinum(IV)chloride will give _____ number of ions on ionisation.

A
4
B
3
C
2
D
5
3
KCET 2021
MCQ (Single Correct Answer)
+1
-0

For the crystal field splitting in octahedral complexes,

A
the energy of the $$e_g$$ orbitals will decrease by $$(3 / 5) \Delta_o$$ and that of the $$t_{2 g}$$ will increase by $$(2 / 5) \Delta_0$$
B
the energy of the $$e_g$$ orbitals will increase by $$(3 / 5) \Delta_o$$ and that of the $$t_{2 g}$$ will decrease by $$(2/5) \Delta_o$$
C
the energy of the $$e_g$$ orbitals will increase by $$(3 / 5) \Delta_o$$ and that of the $$t_{2 g}$$ will increase by $$(2 / 5) \Delta_0$$
D
the energy of the $$e_g$$ orbitals will decrease by $$(3 / 5) \Delta_0$$ and that of the $$t_{2 g}$$ will decrease by $$(2 / 5) \Delta_0$$
4
KCET 2021
MCQ (Single Correct Answer)
+1
-0

The IUPAC name of $$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{CO}_3\right)\right] \mathrm{Cl}$$ is

A
pentaamminecarbonatocobalt (III) chloride
B
carbonatopentamminecobalt (III) chloride
C
pentaamminecarbonatocobaltate (III) chloride
D
pentaammine cobalt (III) carbonate chloride
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