An aqueous solution of $$\mathrm{CuSO}_4$$ is subjected to electrolysis using inert electrodes. The $$\mathrm{pH}$$ of the solution will

Give $$E_{\mathrm{Mn}^{+7} \mid \mathrm{Mn}^{+2}}^0=1.5 \mathrm{~V}$$ and $$E_{\mathrm{Mn}^{+4}\mid \mathrm{Mn}^{+2}}^0=1.2 \mathrm{~V}$$, then $$E_{\mathrm{Mn}^{+7} \mid \mathrm{Mn}^{+4}}^0$$ is

Addition of excess of $$\mathrm{AgNO}_3$$ to an aqueous solution of 1 mole of $$\mathrm{PdCl}_2 \cdot 4 \mathrm{NH}_3$$ gives 2 moles of $$\mathrm{AgCl}$$. The conductivity of this solution corresponds to