1
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The number of ways in which 4 different things can be distributed to 6 persons so that no person gets all the things is
A
1292
B
1296
C
1290
D
4090
2
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If the coefficients of 3 consecutive terms in the expansion of $(1+x)^{23}$ are in arithmetic progression, then those terms are
A
$\mathrm{T}_{10}, \mathrm{~T}_{11}, \mathrm{~T}_{12}$
B
$\mathrm{T}_8, \mathrm{~T}_9, \mathrm{~T}_{10}$
C
$\mathrm{T}_{13}, \mathrm{~T}_{14}, \mathrm{~T}_{15}$
D
$\mathrm{T}_{14}, \mathrm{~T}_{15}, \mathrm{~T}_{16}$
3
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
The numerically greatest term in the expansion of $(3 x-16 y)^{15}$, when $x=\frac{2}{3}$ and $y=\frac{3}{2}$, is
A
13th term
B
14 th term
C
15 th term
D
16 th term
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}$ $+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}$, then $2 A+3 B-C-D+E=$
A
0
B
1
C
-11
D
-39
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