1
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int \frac{d x}{9 \cos ^2 2 x+16 \sin ^2 2 x}=$
A
$\frac{1}{25} \tan ^{-1}\left(\frac{3}{4} \sec ^2 2 x\right)+c$
B
$\frac{1}{25} \tan ^{-1}\left(\frac{4}{3} \sec ^2 2 x\right)+c$
C
$\frac{1}{24} \tan ^{-1}\left(\frac{3}{4} \tan 2 x\right)+c$
D
$\frac{1}{24} \tan ^{-1}\left(\frac{4}{3} \tan 2 x\right)+c$
2
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int \frac{2 \cos 3 x-3 \sin 3 x}{\cos 3 x+2 \sin 3 x} d x=$
A
$\frac{7}{15} \log |\cos 3 x+2 \sin 3 x|-\frac{4}{5} x+c$
B
$-\frac{4}{5} \log |\cos 3 x+2 \sin 3 x|+\frac{7 x}{5}+c$
C
$\frac{7}{5} \log |\cos 3 x+2 \sin 3 x|-\frac{4}{5} x+c$
D
$-\frac{8}{15} \log |\cos 3 x+2 \sin 3 x|+\frac{x}{5}+c$
3
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$ \int_{\frac{-3}{4}}^{\frac{\pi-6}{8}} \log (\sin (4 x+3)) d x= $

A
$-\frac{\pi}{2} \log 2$
B
$-\frac{\pi}{8} \log 2$
C
$-\frac{\pi}{14} \log 2$
D
$-\frac{\pi}{28} \log 2$
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int_0^{16} \frac{\sqrt{x}}{1+\sqrt{x}} d x=$
A
$8+2 \log 2$
B
$8+\log 2$
C
$8+2 \log 5$
D
$4+\log 5$
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