1
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int e^{-2 x}\left(\tan 2 x-2 \sec ^2 2 x \tan 2 x\right) d x=$
A
$e^{-2 x} \tan 2 x+c$
B
$-\frac{e^{-2 x}}{2}\left[\sec ^2 2 x+\tan 2 x\right]+c$
C
$-\frac{e^{-2 x}}{2}\left[\tan 2 x-\sec ^2 2 x\right]+c$
D
$e^{-2 x} \sec ^2 2 x+c$
2
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
If $\int x^3 \sin 3 x d x=f(x) \cos 3 x+g(x) \sin 3 x+C$, then 27 $(f(x)+x g(x))=$
A
$18 x^3+4 x$
B
$8 x$
C
$4 x$
D
$18 x^3+8 x$
3
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int \frac{d x}{9 \cos ^2 2 x+16 \sin ^2 2 x}=$
A
$\frac{1}{25} \tan ^{-1}\left(\frac{3}{4} \sec ^2 2 x\right)+c$
B
$\frac{1}{25} \tan ^{-1}\left(\frac{4}{3} \sec ^2 2 x\right)+c$
C
$\frac{1}{24} \tan ^{-1}\left(\frac{3}{4} \tan 2 x\right)+c$
D
$\frac{1}{24} \tan ^{-1}\left(\frac{4}{3} \tan 2 x\right)+c$
4
TG EAPCET 2024 (Online) 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
$\int \frac{2 \cos 3 x-3 \sin 3 x}{\cos 3 x+2 \sin 3 x} d x=$
A
$\frac{7}{15} \log |\cos 3 x+2 \sin 3 x|-\frac{4}{5} x+c$
B
$-\frac{4}{5} \log |\cos 3 x+2 \sin 3 x|+\frac{7 x}{5}+c$
C
$\frac{7}{5} \log |\cos 3 x+2 \sin 3 x|-\frac{4}{5} x+c$
D
$-\frac{8}{15} \log |\cos 3 x+2 \sin 3 x|+\frac{x}{5}+c$
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