1
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the probability distribution of a random variable $X$ is as follow, then the variance of $X$ is
$X=x$ 2 3 5 9
$P(X=x)$ $k$ $2 k$ $3 k^2$ $k$
A
$\frac{61}{4}$
B
$\frac{7}{2}$
C
12
D
3
2
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The mean of a binomial variate $X \sim B(n, p)$ is 1 . If $n>2$ and $P(X=2)=\frac{27}{128}$, then the variance of the distribution is
A
$\frac{3}{4}$
B
$\frac{1}{4}$
C
$\frac{4}{3}$
D
4
3
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the distance from a variable point $P$ to the point $(4,3)$ is equal to the perpendicular distance from $P$ to the line $x+2 y-1=0$, then the equation of the locus of the point $P$ is
A
$4 x^2+4 x y+y^2-38 x+26 y+124=0$
B
$4 x^2-4 x y+y^2-38 x-26 y+124=0$
C
$4 x^2-4 x y+y^2+38 x+26 y+124=0$
D
$4 x^2-4 x y+y^2-38 x+26 y+124=0$
4
TG EAPCET 2024 (Online) 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
$(0, k)$ is the point to which the origin is to be shifted by the translation of the axes so as to remove the first degree terms from the equation $a x^2-2 x y+b y^2-2 x+4 y+1=0$ and $\frac{1}{2} \tan ^{-1}(2)$ is the angle through which the coordinate axes are to be rotated about the origin to remove the $x y$-term from the given equation, then $a+b=$
A
1
B
-2
C
3
D
-4
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