1
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Given the probability density function (p.d.f.) of the random variable X, $f(x) = \dfrac{1}{2a}$, $0 < x < 2a$, $a > 0$
$= 0$, otherwise, then which of the following is correct ?
A
$P\left(X < \dfrac{a}{2}\right) = P\left(X > \dfrac{a}{2}\right)$
B
$P\left(X < \dfrac{a}{2}\right) < P\left(X > \dfrac{3a}{2}\right)$
C
$P\left(X < \dfrac{a}{2}\right) > P\left(X > \dfrac{3a}{2}\right)$
D
$P\left(X < \dfrac{a}{2}\right) = P\left(X > \dfrac{3a}{2}\right)$
2
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Consider a game of tossing a six sided fair die. If the face that comes up is $6$, the player wins Rs. $36$ and he loses Rs. $k^2$, where $k$ is the face that comes up $k = \{1, 2, 3, 4, 5\}$, then the expected winning amount in this game in Rs. is...
A
$\dfrac{19}{6}$
B
$-\dfrac{19}{6}$
C
$\dfrac{3}{2}$
D
$-\dfrac{3}{2}$
3
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
For two vectors $\vec{P}$ and $\vec{Q}$, $\vec{P} \cdot \vec{Q} = |\vec{P} \times \vec{Q}|$
The magnitude of $\vec{R} = \vec{P} + \vec{Q}$ is ($\cos 45^\circ = \dfrac{1}{\sqrt{2}}$) ?
A
$\sqrt{P^2 + Q^2}$
B
$\dfrac{\sqrt{P^2 + Q^2}}{\sqrt{2}}$
C
$\sqrt{P^2 + Q^2 + \dfrac{PQ}{\sqrt{2}}}$
D
$\sqrt{P^2 + Q^2 + \sqrt{2}\,PQ}$
4
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two stones of masses $m$ and $3m$ are whirled in horizontal circles, the heavier one in a radius $\dfrac{r}{3}$ and the lighter one in radius $r$. When both the stones experience same centripetal forces, the tangential speed of lighter stone is '$n$' times that of the value of heavier stone. The value of '$n$' is
A
$1$
B
$2$
C
$3$
D
$4$

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