1
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
A particle is fired straight up from the ground. Its height in feet after $t$ second is given by $s(t) = 128t - 16t^2$. The velocity of the particle when it hits the ground is...
A
$-128$ ft/sec
B
$128$ ft/sec
C
$0$ ft/sec
D
$256$ ft/sec
2
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of $c$ satisfied by the Rolle's theorem for the function $f(x) = x^2(1 - x)^2$, $x \in [0, 1]$ is...
A
$0$
B
$1$
C
$\dfrac{1}{2}$
D
$-1$
3
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of integral $\displaystyle\int \dfrac{dx}{\sin^2 x + \tan^2 x}$ is...
A
$\dfrac{-1}{2\tan x} + \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
B
$\dfrac{-1}{2\tan x} - \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
C
$\dfrac{1}{2\tan x} - \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
D
$\dfrac{1}{2\tan x} + \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
4
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of integral $\displaystyle\int \dfrac{\sqrt{x^2 + 1}\,[\log(x^2 + 1) - 2\log x]}{x^4}\,dx$ is equal to...
A
$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) + \dfrac{2}{9}\right] + c$
B
$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) - \dfrac{2}{9}\right] + c$
C
$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) + \dfrac{2}{3}\right] + c$
D
$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) - \dfrac{2}{3}\right] + c$

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