MHT CET 2026 19th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

The shaded region in the provided graph represents the solution set for which of the following systems of linear inequalities?

$2x + y \geq 2,\ x - y \geq 1,\ x + 2y \leq 8,\ x \geq 0,\ y \geq 0$

$x + 2y \geq 2,\ x - y \geq 1,\ x + 2y \leq 8,\ x \geq 0,\ y \geq 0$

$2x + y \geq 2,\ x - y \leq 1,\ x + 2y \leq 8,\ x \geq 0,\ y \geq 0$

$2x + y \geq 2,\ x - y \leq 1,\ 2x + y \leq 8,\ x \geq 0,\ y \geq 0$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

If in $6$ trials, X is a binomial random variable which follows the relation $9P(x = 4) = P(x = 2)$, then the probability of failure is...

$0.125$

$0.25$

$0.375$

$0.75$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Given the probability density function (p.d.f.) of the random variable X, $f(x) = \dfrac{1}{2a}$, $0 < x < 2a$, $a > 0$
$= 0$, otherwise, then which of the following is correct ?

$P\left(X < \dfrac{a}{2}\right) = P\left(X > \dfrac{a}{2}\right)$

$P\left(X < \dfrac{a}{2}\right) < P\left(X > \dfrac{3a}{2}\right)$

$P\left(X < \dfrac{a}{2}\right) > P\left(X > \dfrac{3a}{2}\right)$

$P\left(X < \dfrac{a}{2}\right) = P\left(X > \dfrac{3a}{2}\right)$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Consider a game of tossing a six sided fair die. If the face that comes up is $6$, the player wins Rs. $36$ and he loses Rs. $k^2$, where $k$ is the face that comes up $k = \{1, 2, 3, 4, 5\}$, then the expected winning amount in this game in Rs. is...

$\dfrac{19}{6}$

$-\dfrac{19}{6}$

$\dfrac{3}{2}$

$-\dfrac{3}{2}$

PREVIOUS NEXT