MHT CET 2026 19th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

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The logical statement $(p \vee q) \wedge [(\sim p \wedge q) \vee (p \wedge \sim q)] \wedge \sim q$ is logically equivalent to ...

$p \wedge \sim q$

$\sim p \wedge q$

$p \wedge q$

$\sim p \vee \sim q$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Which of the following logical statements is a tautology?

$[(p \rightarrow q) \wedge \sim q] \rightarrow \sim p$

$(p \rightarrow q) \wedge (p \wedge \sim q)$

$[(p \vee q) \wedge \sim p] \wedge \sim q$

$[(p \vee \sim q) \vee (\sim p \wedge q)] \wedge r$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

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In $\triangle ABC$, with usual notations, if the sides $a$, $b$ and $c$ are in the ratio $18 : 17 : 7$, then $\cot\dfrac{A}{2} : \cot\dfrac{B}{2} : \cot\dfrac{C}{2} =$

$4 : 3 : 14$

$14 : 4 : 3$

$3 : 4 : 14$

$4 : 14 : 3$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

If $A = [a_{ij}]_{3\times3}$, where $a_{ij} = \begin{cases} 1, & \text{if } i+j \text{ is even} \\ 0, & \text{if } i+j \text{ is odd} \end{cases}$, then $\text{adj}(A) = \ldots$ ..

$\begin{bmatrix} 0 & 1 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 0 \end{bmatrix}$

$\begin{bmatrix} 1 & 0 & -1 \\ 0 & 0 & 0 \\ -1 & 0 & 1 \end{bmatrix}$

$\begin{bmatrix} 0 & 1 & 0 \\ 1 & 1 & 1 \\ 0 & 1 & 0 \end{bmatrix}$

$\begin{bmatrix} 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 1 & 1 \end{bmatrix}$

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