MHT CET 2026 16th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 16th April Evening Shift

MCQ (Single Correct Answer)

-0

If $\cot[f(x)] = \dfrac{3x - x^3}{1 - 3x^2}$ and $\sin[g(x)] = \dfrac{1 - x^2}{1 + x^2}$, then $\lim\limits_{x \to t}\dfrac{f(x) - f(t)}{g(x) - g(t)} = \ldots$

$\dfrac{3}{2(1 + t^2)}$

$\dfrac{3}{2}$

$\dfrac{5}{2}$

$-\dfrac{5}{2(1 + t^2)}$

MHT CET 2026 16th April Evening Shift

MCQ (Single Correct Answer)

-0

If $y = \cos^{-1}\left(\dfrac{1 - 4^x}{1 + 4^x}\right)$, then $\dfrac{dy}{dx}$ at $x = 1$ is

$\dfrac{4\log 2}{5}$

$\dfrac{\log 2}{5}$

$\dfrac{2\log 8}{5}$

$\dfrac{5\log 8}{2}$

MHT CET 2026 16th April Evening Shift

MCQ (Single Correct Answer)

-0

A cylindrical tank without a top lid is being manufactured to hold a fixed volume of $125\pi$ cubic cm. The minimum surface area required to construct this tank is ............square cm

$75\pi$

$50\pi$

$25\pi$

$125\pi$

MHT CET 2026 16th April Evening Shift

MCQ (Single Correct Answer)

-0

A spherical snow ball is melting so that its volume is decreasing at the rate of 8 c.c./sec then the rate of change of radius when the radius is 2 cm, is :

The radius is increasing at the rate of $\dfrac{1}{2\pi}\ \text{cm/s}$

The radius is decreasing at the rate of $\dfrac{1}{2\pi}\ \text{cm/s}$

The radius is increasing at the rate of $\dfrac{1}{\pi}\ \text{cm/s}$

The radius is decreasing at the rate of $\dfrac{1}{\pi}\ \text{cm/s}$

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