1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the truth value of the compound statement $[(p \leftrightarrow q) \wedge (q \to r) \wedge \sim r] \to (p \wedge \sim q)$ is false, then the truth values of the statement patterns $(p \to q) \leftrightarrow (q \to r)$ and $\sim(p \vee r) \to (q \wedge p)$ are, respectively ...
A
$(T, T)$
B
$(T, F)$
C
$(F, T)$
D
$(F, F)$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The negation of the contrapositive of the statement $(p \vee \sim q) \to (p \wedge \sim q)$ is
A
$(p \wedge \sim q) \vee (\sim p \wedge \sim q)$
B
$(\sim p \wedge q) \vee (p \wedge \sim q)$
C
$(\sim p \vee \sim q) \wedge (p \vee q)$
D
$(\sim p \vee q) \wedge (p \vee \sim q)$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
In triangle ABC, with usual notations, if $a = 4, b = 5$ and $c = 6$, then angle C is equal to...
A
$A$
B
$2A$
C
$3A$
D
$\dfrac{A}{2}$
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $A = \begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$, $B^{-1} = \begin{bmatrix} \dfrac{1}{5} & \dfrac{2}{5} \\ \dfrac{2}{5} & -\dfrac{1}{5} \end{bmatrix}$, then $(AB)^{-1} = $
A
$\dfrac{1}{95}\begin{bmatrix} 8 & -1 \\ -1 & 12 \end{bmatrix}$
B
$\dfrac{1}{95}\begin{bmatrix} 12 & -1 \\ -1 & 8 \end{bmatrix}$
C
$\dfrac{1}{95}\begin{bmatrix} -12 & 1 \\ 1 & -8 \end{bmatrix}$
D
$\dfrac{1}{95}\begin{bmatrix} -8 & 1 \\ 1 & -12 \end{bmatrix}$

MHT CET Papers

All year-wise previous year question papers