1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $e^x + e^{f(x)} = e$, then the domain of $f(x)$ is
A
$(1, \infty)$
B
$(-\infty, 1)$
C
$(-\infty, \infty)$
D
$(-\infty, 0)$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the function f is continuous at $x = \pi$, where $f(x) = \dfrac{1 - \cos[7(x - \pi)]}{5(x - \pi)^2}$, for $x \neq \pi$, then $f(\pi) = $
A
$\dfrac{49}{4}$
B
$\dfrac{4}{49}$
C
$\dfrac{49}{10}$
D
$\dfrac{10}{49}$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let f(x) be a twice differentiable function such that $f''(x) = -f(x)$, $f'(x) = g(x)$ and $h(x) = \{f(x)\}^2 + \{g(x)\}^2$. If $h(5) = 11$, then $h(10)$ is equal to ...
A
$11$
B
$22$
C
$0$
D
Not defined
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\cot[f(x)] = \dfrac{3x - x^3}{1 - 3x^2}$ and $\sin[g(x)] = \dfrac{1 - x^2}{1 + x^2}$, then $\lim\limits_{x \to t}\dfrac{f(x) - f(t)}{g(x) - g(t)} = \ldots$
A
$\dfrac{3}{2(1 + t^2)}$
B
$\dfrac{3}{2}$
C
$\dfrac{5}{2}$
D
$-\dfrac{5}{2(1 + t^2)}$

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