1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $n$ is a positive integer, then $(1 + i\sqrt{3})^{2n} + (1 - i\sqrt{3})^{2n}$ is equal to .........
A
$2^{2n+1}\cos\left(\dfrac{2n\pi}{3}\right)$
B
$2^{2n}\cos\left(\dfrac{n\pi}{3}\right)$
C
$2^{2n+1}\cos\left(\dfrac{n\pi}{3}\right)$
D
$2^n\cos\left(\dfrac{2n\pi}{3}\right)$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The number of 4-letter words formed from the English alphabet such that there are exactly 2 vowels and 2 consonants and no vowel is repeated, but consonants may be repeated is:
A
${}^{4}C_2 \times {}^{5}C_2 \times (21)^2$
B
${}^{4}C_2 \times {}^{5}C_2 \times {}^{21}C_2$
C
${}^{4}C_2 \times {}^{5}P_2 \times {}^{21}P_2$
D
${}^{4}C_2 \times {}^{5}P_2 \times (21)^2$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $\cos(60^\circ - A)\cdot\cos A\cdot\cos(60^\circ + A)$ is
A
$\dfrac{1}{4}\cos 3A$
B
$\sin 3A$
C
$\cos 3A$
D
$\dfrac{1}{4}\sin 3A$
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the equation $\cot\theta \cdot \cot 2\theta = 1$ is...
A
$\theta = n\pi \pm \dfrac{\pi}{6}, n \in Z$
B
$\theta = n\pi \pm \dfrac{\pi}{3}, n \in Z$
C
$\theta = n\pi \pm \dfrac{\pi}{4}, n \in Z$
D
$\theta = n\pi \pm \dfrac{\pi}{8}, n \in Z$

MHT CET Papers

All year-wise previous year question papers