MHT CET 2026 13th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

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The difference between the maximum value and minimum value of the objective function $z = 3x + 5y$ of a linear programming problem subject to constraints $5x + 10y \leq 50$, $x + y \geq 1$, $y \leq 4$ and $x \geq 0, y \geq 0$ is $3\lambda$. Then the value of $\lambda$ is

$3$.

$6$.

$9$.

$27$.

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

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In a multiple-choice examination, there are $10$ questions with one correct option out of $4$ options for each question. A student gets $4$ marks for each correct answer and $1$ mark is deducted for each incorrect answer. The probability that a student, guessing randomly on every question, scores $30$ marks in this exam is...

$\dfrac{45}{4^{10}}$

$\dfrac{135}{4^{10}}$

$\dfrac{405}{4^{10}}$

$\dfrac{810}{4^{10}}$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

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It is known that a box of $8$ batteries contains $3$ defective pieces and a person randomly selects $2$ batteries from this box. Then the probability distribution of the number of defective batteries is

$X = x$	$0$	$1$	$2$
$P(X = x)$	$\dfrac{10}{28}$	$\dfrac{15}{28}$	$\dfrac{3}{28}$

$X = x$	$1$	$2$	$3$
$P(X = x)$	$\dfrac{10}{28}$	$\dfrac{15}{28}$	$\dfrac{3}{28}$

$X = x$	$0$	$1$	$2$
$P(X = x)$	$\dfrac{15}{28}$	$\dfrac{10}{28}$	$\dfrac{3}{28}$

$X = x$	$1$	$2$	$3$
$P(X = x)$	$\dfrac{15}{28}$	$\dfrac{10}{28}$	$\dfrac{3}{28}$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

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A certain disease has a prevalence of $1\%$ in the population. A diagnostic test for the disease has a sensitivity of $98\%$ and a specificity of $95\%$. If a person from this population tests positive, then the probability that they actually have the disease is...

$98\%$

$95\%$

$16.5\%$

$1\%$

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