1
MHT CET 2026 13th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\int \dfrac{x+1}{x^2+1}dx = \tan^{-1}x + g(x) + c$, where $c$ is constant of integration, then the function $g(x)$ is monotonically increasing in the interval
A
$R^+$
B
$R^-$
C
$R$
D
$R - \{0\}$
2
MHT CET 2026 13th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int \sqrt{1+\sin x}\,dx$ is equal to
A
$2\sqrt{2}\sin\left(\dfrac{x}{2} - \dfrac{\pi}{4}\right) + c$
B
$2\sqrt{2}\sin\left(\dfrac{x}{2} + \dfrac{\pi}{4}\right) + c$
C
$\sqrt{2}\sin\left(\dfrac{x}{2} - \dfrac{\pi}{4}\right) + c$
D
$\sqrt{2}\sin\left(\dfrac{x}{2} + \dfrac{\pi}{4}\right) + c$
3
MHT CET 2026 13th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\int_0^a (x^2 - 4x + 1)dx = 6$, then the real value of $a$ is
A
$4$
B
$6$
C
$3$
D
$-3$
4
MHT CET 2026 13th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\int_{\pi/6}^{\pi/3} \dfrac{1}{1+\sin x + \cos x}dx = \log 2$, then the value of $\int_{\pi/6}^{\pi/3} \dfrac{\cos x}{1+\sin x + \cos x}dx = $ ............
A
$\dfrac{\pi}{12} - \dfrac{1}{2}\log 2$
B
$\dfrac{\pi}{12} - \dfrac{1}{3}\log 2$
C
$\dfrac{\pi}{6} - \dfrac{1}{2}\log 2$
D
$\dfrac{\pi}{12} - \dfrac{1}{4}\log 2$

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