MHT CET 2026 13th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

The differential equation of $3y = \sqrt[3]{x+c}$ is

$\dfrac{dy}{dx} = \dfrac{1}{9y^2}$

$\dfrac{dy}{dx} = \dfrac{1}{27y^2}$

$\dfrac{dy}{dx} = \dfrac{1}{81y^2}$

$\dfrac{dy}{dx} = \dfrac{1}{36y^2}$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

The general solution of the differential equation $(x+y)\dfrac{dy}{dx} = 1$ is

$x + y + 1 = c$, where $c$ is a constant of integration

$x + y + 1 = ce^y$, where $c$ is a constant of integration

$x + y + 1 = ce^{-y}$, where $c$ is a constant of integration

$x + y - 1 = ce^{-y}$, where $c$ is a constant of integration

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

A body cools according to Newton's law of cooling from $100^\circ$C to $60^\circ$C in $20$ minutes. The temperature of the surroundings being $20^\circ$C, then the total time required for the body to cool down to $30^\circ$C is

$90$ minutes

$1$ hour and $10$ minutes

$80$ minutes

$60$ minutes

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

If $\bar{a} = \hat{i} + \hat{j}$ and $\bar{b} = \hat{i} - \hat{k}$, then the point of intersection of the lines $\bar{r} \times \bar{a} = \bar{b} \times \bar{a}$ and $\bar{r} \times \bar{b} = \bar{a} \times \bar{b}$ is

$(2, 1, -1)$

$(2, -1, 1)$

$(0, 1, 1)$

$(0, -1, 1)$

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