MHT CET 2026 13th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

The vector equation of the plane which is at a distance of $5$ units from the origin and normal to the vector $2\hat{i} + \hat{j} - 2\hat{k}$ is

$\vec{r} \cdot (2\hat{i} + \hat{j} - 2\hat{k}) = 12$

$\vec{r} \cdot (2\hat{i} + \hat{j} - 2\hat{k}) = 15$

$\vec{r} \cdot (2\hat{i} + \hat{j} - 2\hat{k}) = 9$

$\vec{r} \cdot (2\hat{i} + \hat{j} - 2\hat{k}) = 18$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

The equation of a line passing through a point $(4, -2, 3)$ and perpendicular to the XZ-plane is....

$\bar{r} = (4\hat{i} - 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} + \hat{k})$

$\bar{r} = (4\hat{i} - 2\hat{j} + 3\hat{k}) + \lambda(\hat{i})$

$\bar{r} = (4\hat{i} - 2\hat{j} + 3\hat{k}) + \lambda(\hat{j})$

$\bar{r} = (4\hat{i} - 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} - \hat{k})$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

The equation of the plane passing through the intersection of planes $2x - y + z = 3$, $4x - 3y + 5z = -9$ and parallel to the line $\dfrac{x+1}{2} = \dfrac{y+3}{4} = \dfrac{z-3}{5}$ is...

$11x - 3y - 2z - 54 = 0$

$11x + 3y - 2z - 54 = 0$

$11x - 3y + 2z - 54 = 0$

$11x - 3y - 2z + 54 = 0$

MHT CET 2026 13th April Evening Shift

MCQ (Single Correct Answer)

-0

If a line makes angles $\alpha, \beta, \gamma$ with the coordinate axes, then the sum of values of $\sin^2\alpha + \sin^2\beta + \sin^2\gamma$ and $\cos 2\alpha + \cos 2\beta + \cos 2\gamma$ is ...

$5$

$0$

$3$

$1$

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