MHT CET 2022 11th August Evening Shift | MHT CET Year Wise Previous Years Questions

Calculate $$\wedge_0$$ of $$\mathrm{CH}_2 \mathrm{ClCOOH}$$ if $$\wedge_0$$ for $$\mathrm{HCl}, \mathrm{KCl}$$ and $$\mathrm{CH}_2 \mathrm{ClCOOK}$$ are $$4.2,1.5$$ and $$1.1 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$ respectively?

$$2.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$3.8 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$1.9 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$4.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

MHT CET 2022 11th August Evening Shift

MCQ (Single Correct Answer)

-0

Identify the product A in the following reaction.

MHT CET 2022 11th August Evening Shift Chemistry - Hydrocarbons Question 15 English

$$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$$

$$\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$$

$$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_3$$

$$\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$$

MHT CET 2022 11th August Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the amount of solute dissolved in 160 gram solvent that boils at $$85^{\circ} \mathrm{C}$$, the molar mass of solute is $$120 \mathrm{~g} \mathrm{~mol}^{-1}$$. $$\left(\mathrm{K}_{\mathrm{b}}\right.$$ for solvent $$=2.7^{\circ} \mathrm{C} \mathrm{~kg} \mathrm{~mol}^{-1}$$ and boiling point of solvent $$=76^{\circ} \mathrm{C}$$)

42 gram

60 gram

64 gram

50 gram

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