1
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

A parallel plate air capacitor has a uniform electric field 'E' in the space between the plates. Area of each plate is A and the distance between the plates is '$$\mathrm{d}$$'. The energy stored in the capacitor is $$\left[\varepsilon_0=\right.$$ permittivity of free space)

A
$$2 \varepsilon_0 \mathrm{EAd}$$
B
$$\frac{1}{2} \varepsilon_0 \mathrm{E}^2 \mathrm{Ad}$$
C
$$\frac{\varepsilon_0 \mathrm{E}^2}{2 \mathrm{Ad}}$$
D
$$\frac{\mathrm{E}^2 \mathrm{Ad}}{2 \varepsilon_0}$$
2
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two massless springs of spring constant $$\mathrm{K}_1$$ and $$\mathrm{K}_2$$ are connected one after the other forming a single chain, suspended vertically and certain mass is attached to the free end. If '$$e_1$$' and '$$e_2$$' are their respective extensions and '$$\mathrm{f}$$' is their stretching force, the total extension produced is

A
$$\mathrm{f}\left(\frac{1}{\mathrm{~K}_1}+\frac{1}{\mathrm{~K}_2}\right)$$
B
$$\mathrm{f}\left(\frac{1}{\mathrm{~K}_1}-\frac{1}{\mathrm{~K}_2}\right)$$
C
$$\mathrm{f}\left(\mathrm{K}_1+\mathrm{K}_2\right)$$
D
$$\mathrm{f}\left(\mathrm{K}_1-\mathrm{K}_2\right)$$
3
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

The time taken by a particle executing simple harmonic motion of period '$$\mathrm{T}$$', to move from the mean position to half the maximum displacement is

A
$$\frac{\mathrm{T}}{12} \mathrm{~s}$$
B
$$\frac{\mathrm{T}}{2} \mathrm{~s}$$
C
$$\frac{\mathrm{T}}{4} \mathrm{~s}$$
D
$$\frac{\mathrm{T}}{6} \mathrm{~s}$$
4
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

Using Bohr's model, the orbital period of electron in hydrogen atom in the $$\mathrm{n}^{\text {th }}$$ orbit is $$\left(\varepsilon_0=\right.$$ permittivity of vacuum, $$\mathrm{h}=$$ Planck's constant, $$\mathrm{m}=$$ mass of electron, $$\mathrm{e}=$$ electronic charge)

A
$$\frac{4 \varepsilon_0 \mathrm{nh}^3}{\mathrm{me}^2}$$
B
$$\frac{4 \varepsilon_0 \mathrm{n}^2 \mathrm{~h}^2}{\mathrm{me}^2}$$
C
$$\frac{4 \varepsilon_0^2 n^3 h^3}{m e^4}$$
D
$$\frac{4 \varepsilon_0^2 \mathrm{n}^2 \mathrm{~h}^3}{m \mathrm{e}^3}$$
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