1
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\overrightarrow{\mathrm{a}}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}, \overline{\mathrm{b}}=-\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}, \overline{\mathrm{c}}=3 \hat{\mathrm{i}}+\hat{\mathrm{j}}$$ and $$\overline{\mathrm{a}}+\lambda \overline{\mathrm{b}}$$ is perpendicular to $$\overline{\mathrm{c}}$$, then $$\lambda=$$

A
5
B
2
C
3
D
4
2
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If two lines represented by $$a x^2+2 h x y+b y^2=0$$ makes angles $$\alpha$$ and $$\beta$$ with positive direction of $$\mathrm{X}$$-axis, then $$\tan (\alpha+\beta)=$$

A
$$\frac{2 h}{b-a}$$
B
$$\frac{2 h}{a-b}$$
C
$$\frac{h}{a+b}$$
D
$$\frac{2 h}{a+b}$$
3
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\tan ^{-1}\left[\frac{\sqrt{1+x^2}-\sqrt{1-x^2}}{\sqrt{1+x^2}+\sqrt{1-x^2}}\right]=\alpha$$, then the value of $$\sin 2 \alpha$$ is

A
$$x^3$$
B
$$\sqrt{x}$$
C
$$x$$
D
$$\mathrm{x}^2$$
4
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of the differential equation $$\frac{d y}{d x}=2^{y-x}$$ is

A
$$2^x-2^y=c$$
B
$$\frac{1}{2^x}-\frac{1}{2^y}=c$$
C
$$\frac{1}{2^x}+\frac{1}{2^y}=c$$
D
$$2^x+2^y=c$$
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