1
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{A}=\left[\begin{array}{ccc}1 & 2 & 3 \\ -1 & 1 & 2 \\ 1 & 2 & 4\end{array}\right]$$, then $$\mathrm{A}(\operatorname{adj} \mathrm{A})=$$

A
$$\left[\begin{array}{ccc}-1 / 3 & 0 & 0 \\ 0 & -1 / 3 & 0 \\ 0 & & -1 / 3\end{array}\right]$$
B
$$\left[\begin{array}{lll}3 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 3\end{array}\right]$$
C
$$\left[\begin{array}{ccc}1 & 2 & 3 \\ -1 & 1 & 2 \\ 1 & 2 & 4\end{array}\right]$$
D
$$\left[\begin{array}{ccc}1 & -1 & 1 \\ 2 & 1 & 2 \\ 3 & 2 & 4\end{array}\right]$$
2
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

A random variable X has the following probability distribution

$$x$$ 0 1 2 3 4 5 6 7 8
$$P(X=x)$$ K 2K 3K 4K 4K 3K 2K K K

Then $$\mathrm{P}(3<\mathrm{x} \leq 6)=$$

A
$$\frac{3}{7}$$
B
$$\frac{4}{7}$$
C
$$\frac{13}{21}$$
D
$$\frac{8}{21}$$
3
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$x=-2$$ and $$x=4$$ are the extreme points of $$y=x^3-\alpha x^2-\beta x+5$$, then

A
$$\alpha=3, \beta=24$$
B
$$\alpha=-24, \beta=-3$$
C
$$\alpha=-3, \beta=-24$$
D
$$\alpha=24, \beta=3$$
4
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The coordinates of the foot of the perpendicular drawn from the origin to the plane $$2 x+y-2 z=18$$ are

A
$$(4,2,-4)$$
B
$$(1,2,-3)$$
C
$$(4,2,4)$$
D
$$(4,-2,-4)$$
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