MHT CET 2019 2nd May Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

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The real force ' $F$ ' acting on a particle of mass $m$ ' performing circular motion acts along the radius of circle ' $r$ ' and is directed towards the centre of circle. The square root of magnitude of such force is ( $T=$ periodic time)

$\frac{2 \pi}{T} \sqrt{m r}$

$\frac{T m r}{4 \pi}$

$\frac{2 \pi T}{\sqrt{m r}}$

$\frac{T^2 m r}{4 \pi}$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

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Dimensions of Gyromagnetic ratio are

$\left[L^1 M^0 T^1 I^1\right]$

$\left[L^0 M^{-1} T^1 I^1\right]$

$\left[L^1 M^0 T^0 I^{-1}\right]$

$\left[L^{-1} M^0 T^1 I^1\right]$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

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The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

$\frac{v^2}{2\left(\frac{m}{e}\right)}$

$\frac{v^2}{2\left(\frac{e}{m}\right)}$

$\frac{v^2}{\left(\frac{e}{m}\right)}$

$\frac{v^2}{\left(\frac{m}{e}\right)}$

MHT CET 2019 2nd May Morning Shift

MCQ (Single Correct Answer)

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The equi-convex lens has a focal length ' $f$ '. If the lens is cut along the line perpendicular to the principal axis and passing through the pole, what will be the focal length of any half part?

$\frac{f}{2}$

$2f$

$\frac{3 f}{2}$

$f$