1
MHT CET 2019 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the function $f(x)=\frac{\log (1+a x)-\log (1-b x)}{x}$ $x \neq 0$ is continuous at $x=0$ then, $f(0)=\ldots \ldots$

A
$\log a-\log b$
B
$a+b$
C
$\log a+\log b$
D
$a-b$
2
MHT CET 2019 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The co-ordinates of the foot of perpendicular drawn from origin to the plane $2 x-y+5 z-3=0$ are $\ldots \ldots$

A
$\left(\frac{2}{\sqrt{30}}, \frac{-1}{\sqrt{30}}, \frac{5}{\sqrt{30}}\right)$
B
$(2,-1,5)$
C
$\left(\frac{2}{3}, \frac{-1}{3}, \frac{5}{3}\right)$
D
$\left(\frac{1}{5}, \frac{-1}{10}, \frac{1}{2}\right)$
3
MHT CET 2019 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\int \frac{\sqrt{x^2-a^2}}{x} d x=\ldots \ldots$$

A
$\sqrt{x^2-a^2}-a \cos ^{-1}\left(\frac{a}{x}\right)+c$
B
$x \sqrt{x^2-a^2}-\frac{1}{a} \tan ^{-1}\left(\frac{x}{a}\right)+c$
C
$\sqrt{x^2-a^2}+a \sec ^{-1}\left(\frac{x}{a}\right)+c$
D
$\sqrt{x^2-a^2}+\frac{1}{x} \sec ^{-1}(x)+c$
4
MHT CET 2019 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The maximum value of $z=9 x+11 y$ subject to $3 x+2 y \leq 12,2 x+3 y \leq 12, x \geq 0, y \geq 0$ is $\ldots \ldots$.

A
44
B
54
C
36
D
48
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