MHT CET 2019 2nd May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

When the electron in hydrogen atom jumps from fourth Bohr orbit to second Bohr orbit, one gets the

second line of Balmer series

first line of Balmer series

first line of Pfund series

second line of Paschen series

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

Light of wavelength ' $\lambda$ ' is incident on a single slit of width ' $a$ ' and the distance between slit and screen is ' $D$ '. In diffraction pattern, if slit width is equal to the width of the central maximum then ' $D$ ' is equal to

$\frac{a}{2 \lambda}$

$\frac{a^2}{2 \lambda}$

$\frac{a}{\lambda}$

$\frac{a^2}{\lambda}$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

In U.C.M., when time interval $\delta t \rightarrow 0$, the angle between change in velocity ( $\delta \mathbf{v}$ ) and linear velocity $(\boldsymbol{v})$ will be

$0^\circ$

$90^\circ$

$180^\circ$

$45^\circ$

MHT CET 2019 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

A stretched string fixed at both ends has ' $m$ ' nodes, then the length of the string will be

$(m-1) \frac{\lambda}{2}$

$\frac{(m+1) \lambda}{2}$

$\frac{m \lambda}{2}$

$(m-2) \frac{\lambda}{2}$