1
KCET 2023
MCQ (Single Correct Answer)
+1
-0

If $$A=\left[\begin{array}{cc}1 & \tan \alpha / 2 \\ -\tan \alpha / 2 & 1\end{array}\right]$$ and $$A B=I$$, then $$B$$ is equal to

A
$$\cos ^2 \alpha / 2 \cdot A$$
B
$$\cos ^2 \alpha / 2 \cdot I$$
C
$$\sin ^2 \alpha / 2 \cdot A$$
D
$$\cos ^2 \alpha / 2 \cdot A^T$$
2
KCET 2023
MCQ (Single Correct Answer)
+1
-0

If $$u=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$$ and $$v=\tan ^{-1}\left(\frac{2 x}{1-x^2}\right)$$, then $$\frac{d u}{d v}$$ is

A
2
B
$$\frac{1-x^2}{1+x^2}$$
C
1
D
$$\frac{1}{2}$$
3
KCET 2023
MCQ (Single Correct Answer)
+1
-0

The distance '$$s$$' in meters travelled by a particle in '$$t$$' seconds is given by $$s=\frac{2 t^3}{3}-18 t+\frac{5}{3}$$. The acceleration when the particle comes to rest is :

A
$$10 \mathrm{~m}^2 / \mathrm{s}$$
B
$$12 \mathrm{~m}^2 / \mathrm{s}$$
C
$$18 \mathrm{~m}^2 / \mathrm{s}$$
D
$$3 \mathrm{~m}^2 / \mathrm{s}$$
4
KCET 2023
MCQ (Single Correct Answer)
+1
-0

A particle moves along the curve $$\frac{x^2}{16}+\frac{y^2}{4}=1$$. When the rate of change of abscissa is 4 times that of its ordinate, then the quadrant in which the particle lies is

A
II or IV
B
III or IV
C
II or III
D
I or III
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