1
KCET 2023
MCQ (Single Correct Answer)
+1
-0

A parallel plate capacitor of capacitance $$C_1$$ with a dielectric slab in between its plates is connected to a battery. It has a potential difference $$V_1$$ across its plates. When the dielectric slab is removed, keeping the capacitor connected to the battery, the new capacitance and potential difference are $$C_2$$ and $$V_2$$ respectively, Then

A
$$V_1=V_2, C_1 < C_2$$
B
$$V_1 > V_2, C_1 > C_2$$
C
$$V_1 < V_2, C_1 > C_2$$
D
$$V_1=V_2, C_1 > C_2$$
2
KCET 2023
MCQ (Single Correct Answer)
+1
-0

A cubical Gaussian surface has side of length $$a=10 \mathrm{~cm}$$. Electric field lines are parallel to $$X$$-axis as shown in figure. The magnitudes of electric fields through surfaces $$A B C D$$ and $$E F G H$$ are $$6 ~\mathrm{kNC}^{-1}$$ and $$9 \mathrm{~kNC}^{-1}$$ respectively. Then, the total charge enclosed by the cube is

[Take, $$\varepsilon_0=9 \times 10^{-12} \mathrm{~Fm}^{-1}$$ ]

KCET 2023 Physics - Electrostatics Question 26 English

A
$$-0.27$$ nC
B
1.35 nC
C
$$-1.35$$ nC
D
0.27 nC
3
KCET 2023
MCQ (Single Correct Answer)
+1
-0

Electric field at a distance $$r$$ from an infinitely long uniformly charged straight conductor, having linear charge density $$\lambda$$ is $$E_1$$. Another uniformly charged conductor having same linear charge density $$\lambda$$ is bent into a semicircle of radius $$r$$. The electric field at its centre is $$E_2$$. Then

A
$$E_2=\pi r E_1$$
B
$$E_2=\frac{E_1}{r}$$
C
$$E_1=E_2$$
D
$$E_1=\pi r E_2$$
4
KCET 2023
MCQ (Single Correct Answer)
+1
-0

A wire of resistance $$R$$ is connected across a cell of emf $$(\varepsilon)$$ and internal resistance $$(r)$$. The current through the circuit is $$I$$. In time $$t$$, the work done by the battery to establish the current $$I$$ is

A
$$\varepsilon I t$$
B
$$\frac{\varepsilon^2 t}{R}$$
C
$$IRt$$
D
$$I^2 R t$$
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